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How can the screens resolution be detected and then set the GUI position to the bottom-left corner of my screen?

Gui, Show, xm -- This gets the GUI to the center left, but I need bottom left. Thanks!

You got close to what you are looking for. The x and y options actually use numbers to specify a screen position. It assumes 0, which is why your xm code put it on the left.

Gui, Show, x0 y%SomeValue%, YourWindowTitle

That will set it to the left, and then offset from the top to SomeValue. If you are aiming for the corner, the built in value A_ScreenHeight can be used, just subtract the height of your GUI.

There is nothing as simple as this for bottom or right.

You must know the size of your gui.
And then you must calculate the window location

With the A_ScreenHeight and the gui height, you can calculate the location of the upper left corner of the window.

there are variables A_ScreenWidth & A_ScreenHeight
http://www.autohotkey.com/docs/Variables.htm#Screen


If you have multiple screens you might need to get the left/to/right/bottom parameters,
see Monitor [, N] in this command http://www.autohotkey.com/docs/commands/SysGet.htm

Here's what I tried:



It is indeed in the bottom left corner like I want, but I would like it to be flush with the top of the windows taskbar, instead of behind it hiding part of the GUI. It should be able to rest along the top of the taskbar. How can I achieve this?

This gets the area not including the taskbar. Then you can do MonRight-MonLeft (and the same for top and bottom) to get the width and height.

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Thanks Frankie.

I've also found this to work:




Full Code

SysGet also has the MonitorWorkArea [, N] sub-command
Same as the above except the area is reduced to exclude the area occupied by the taskbar and other registered desktop toolbars.