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Alright, I'm looking for the best way to go about this...

I have a set of 16 variables. All of these variables contain a hexadecimal value. Let's call the variable names:
C_1, C_2, C_3 [...] C_14, C_15, C_16

Now, all of the values in these variables will be the same... Except one. So say all held the value 0x17232D, but one was 0x3A9DE6. How would I go about finding the one different?

Note, the exact values change. I am pixel searching 16 different areas of the screen and I need to know the one area (or variable) that is a different color then the rest.

Thanks!

Let me clarify, either all the variables with be the exact same, or one will be different. I need to find that one that's different.

Apologies for my many replies, but I realize it's kind of a strange / confusing request. Take the following image for example:


I pixel search and the color of each box is stored in a variable. The colors, however, will differ each time I search, so I can not use an exact value. But once I've got all colors stored in variables, how do I find that box 6 is the one different from the rest?

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Note: My name is all lowercase for a reason.
"I think Bigfoot is blurry, that's the problem. It's not the photographer's fault, Bigfoot is blurry. So there's a large, out-of-focus monster roaming the countryside."

But using that example, it also says that C_5 is different. .

Obviously the easiest way to check if none are different is:


Just dunno how, if one is different, how to figure out which. I'm probably overlooking something...

it IS different. you should just do your code then break the loop when it finds the different color if you don't want it to continue.

i gave you woking code. now you need to adapt it to your needs.

_________________
rawr. be very afraid
*poke*
Note: My name is all lowercase for a reason.
"I think Bigfoot is blurry, that's the problem. It's not the photographer's fault, Bigfoot is blurry. So there's a large, out-of-focus monster roaming the countryside."

No, what I mean is C_4 is the only one that differs from the rest.

Regarding your loop idea.

But what if it is:
C_1:=2
C_2:=3
C_3:=3
C_4:=3
C_5:=3

Breaking the loop when it finds a changed number would break at C_2, when really the different one is C_1.

I deleted my example because it was overly-complex and the next poster posted a much simpler and better solution. The basic idea is.

if (c2=c3) and (c1<>c2)
Msgbox % "C1 is unique"
if (c1=c3) and (c1<>c2)
Msgbox % "C2 is unique"

otherwise loop through all the values until you find one not equal to C1

quite simple if you know that only 1 is different.

if c1 = c2 and c2 = c3 and c1 = c3
you can concluded these 3 are the same, and not an anomoly
(if this doesnt work, try with another random 3 untill they are the same)

check every variable with c1, whichever doesnt match is the odd one out

if c1 = c2 and c2 = c3 then ...

c1 must equal c3 and there is no need to check if c1 = c3

That is true. Infact i also realised, if c1=c2, then they are both not an anaomly, therefore theres no need to check anything else at that point.

This should work for all cases you've described.

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Ooh, this sounds like fun!
First, lets find a number to compare against, then loop through them all:
This of course only works if there is only 1 "odd one out"

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The way I did it was this:
I found a pattern where the value of the one different was always higher then all the others. So I used Hex2Dec() to convert all values to decimal, then simply grabbed the highest. .

I do appreciate and thank you for all your help. It ended up and was about 4 lines of code.