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chipmanners

Post subject: Question about RegExMatch

Posted: February 4th, 2012, 6:36 am

Joined: August 30th, 2007, 9:36 pm
Posts: 90

Hi,

I'm trying to remove any numbers from a phrase unless the number is in words, but not sure how to do this with RegExMatch

for example if my variable was this:
var = I really love my BCM100CM 15 watt Speaker

I would like to only pull out the numbers 15 because there are no words connected to it. So what I would like matched would look something like this:

I love my BCM100CM watt speaker

How would I go about doing this?

Thanks
Chip

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Guest

Post subject:

Posted: February 4th, 2012, 6:48 am

Code:

var = I really love my BCM100CM 15 watt Speaker 
newstring := regexreplace(var, "\s\K(\d+\s)")
msgbox % newstring

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chipmanners

Post subject:

Posted: February 4th, 2012, 7:28 am

Joined: August 30th, 2007, 9:36 pm
Posts: 90

Hi Thanks so much, that worked,

Now what does the \K mean?

also how would I do this if I wanted to only remove the words connected to a number (in example, remove BCM100CM) so the output would look like:

I really love my 15 watt Speaker

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Guest

Post subject:

Posted: February 4th, 2012, 7:43 am

chipmanners wrote:

Now what does the \K mean?

the manual wrote:

The escape sequence \K is similar to a look-behind assertion because it causes any previously-matched characters to be omitted from the final matched string. For example, foo\Kbar matches "foobar" but reports that it has matched "bar".

Quote:

how would I do this if I wanted to only remove the words connected to a number (in example, remove BCM100CM) so the output would look like:

I really love my 15 watt Speaker

Code:

var = I really love my BCM100CM 15 watt Speaker
newstring := regexreplace(var, "\s\K\w+\d+\w+\s")
msgbox % newstring

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sinkfaze

Post subject:

Posted: February 4th, 2012, 5:00 pm

Joined: March 19th, 2008, 12:43 am
Posts: 5482
Location: the tunnel(?=light)

Guest wrote:

Code:

var = I really love my BCM100CM 15 watt Speaker 
newstring := regexreplace(var, "\s\K(\d+\s)")
msgbox % newstring

That doesn't quite get all instances:

Code:

var = I really love my BCM100CM 15 watt Speaker
newstring := regexreplace(var, "\b\d+\b | \b\d+\b")
msgbox % newstring

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