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nado() (2.0)

 
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Trikster



Joined: 15 Jul 2007
Posts: 1224
Location: Enterprise, Alabama
PostPosted: Tue Oct 30, 2007 2:09 am    Post subject: nado() (2.0) Reply with quote
Ok, as I was in Math Class today I was working some problems that had to do with some variables: n, a, and d. It was very annoying to have to work out all of the steps. So I made up a function for it. Via nado() (the variables of the function put together.)

Code:
nado(n, a, d, ByRef OutputVar)
{
   OutputVar := a+(n-1)*d
   }


Examples:

Code:
nado(5, 2, 3, Equation) ; 14

MsgBox,, Answer, %Equation%

nado(1567, 57, 78, Equation) ; 12205

MsgBox,, Answer, %Equation%


Post feedback, please.

Update: v2.0:

Thanks to engunneer, I now have a more responsible method of using this function:

Code:
nado(n, a, d)
{
   Return a+(n-1)*d
   }


Example:

Code:
MsgBox,, Answer, % nado(1,3,5) ; 3


Last edited by Trikster on Tue Oct 30, 2007 2:26 am; edited 2 times in total
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engunneer



Joined: 30 Aug 2005
Posts: 6847
Location: Pacific Northwest, US
PostPosted: Tue Oct 30, 2007 2:19 am    Post subject: Reply with quote
a more "standard" way of doing this would be

Code:

nado(n, a, d)
{
   Return a+(n-1)*d
}


Code:

Equation := nado(1,3,5)

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Trikster



Joined: 15 Jul 2007
Posts: 1224
Location: Enterprise, Alabama
PostPosted: Tue Oct 30, 2007 2:20 am    Post subject: Reply with quote
I know of this method of well, whatever you call it. And I tried it earlier without any success with yours, or my own code used.

Edit: Never mind, I got it to work by changing the example to the following:

Code:
MsgBox,, Answer, % nado(1,3,5)
Thanks.
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steliyan



Joined: 20 Apr 2007
Posts: 31
PostPosted: Tue Oct 30, 2007 6:30 am    Post subject: Reply with quote
I guess you're talking about arithmetic progression?
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Trikster



Joined: 15 Jul 2007
Posts: 1224
Location: Enterprise, Alabama
PostPosted: Tue Oct 30, 2007 3:08 pm    Post subject: Reply with quote
I belive so, I'm in second block right now. I can find out in a sec.
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