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Help with adding to Strings

 
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Highly



Joined: 29 Aug 2009
Posts: 4
PostPosted: Sat Aug 29, 2009 1:18 am    Post subject: Help with adding to Strings Reply with quote
Hi, I've been using AHK and this community for quite some time and am asking for a bit of help.

Here's my problem; I have a string, and I want to add to that string. The string starts out as "a", and is supposed to add _Blue, _Green, _Red, _Yellow sequentially to the string(So it would eventually read, "_Blue_Blue_Red_Yellow_red" or something similar), but it's not working

Here's the code

Code:
Seq = a
Loop
{
PixelGetColor, Blue, 367, 367 []
if (Blue = 0xFEEE7F){
  Seq += _Blue
  }
PixelGetColor, Red, 285, 285 []
if (Red = 0x8F8FF5){
  Seq += _Red
  }
PixelGetColor, Green, 285, 365 []
if (Green = 0x7CFFD7){
  Seq += _Green
  }
PixelGetColor, Yellow, 365, 285 []
if (Yellow = 0x9AFEFB){
  Seq += _Yellow
  }
GetKeyState, state, Shift
if state = D
    MsgBox %Seq%
}
return


FYI, Seq is supposed to be the string, and the "Seq += _Yellow" wtc, are where I want to add the words infront of the string.

I've spent a couple of hours going through the manual, and there's virtually nothing on handling strings. Thanks in advance.
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purloinedheart



Joined: 04 Apr 2008
Posts: 537
Location: Canada
PostPosted: Sat Aug 29, 2009 1:24 am    Post subject: Reply with quote
Code:

Var .= "String"


Hope that's what you are looking for
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Highly



Joined: 29 Aug 2009
Posts: 4
PostPosted: Sat Aug 29, 2009 1:26 am    Post subject: Reply with quote
PurloinedHeart wrote:
Code:

Var .= "String"


Hope that's what you are looking for

I'm going to try this one out, but a little help as to what it does?
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horntail



Joined: 03 Aug 2009
Posts: 69
Location: UK
PostPosted: Sat Aug 29, 2009 1:31 am    Post subject: Reply with quote
PurloinedHeart wrote:
Code:

Var .= "String"


Hope that's what you are looking for


nice edit there, i was just going to correct you PurloinedHeart Smile

the .= means that the following will be added to the var, instead of replacing it
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Highly



Joined: 29 Aug 2009
Posts: 4
PostPosted: Sat Aug 29, 2009 1:37 am    Post subject: Reply with quote
horntail wrote:
PurloinedHeart wrote:
Code:

Var .= "String"


Hope that's what you are looking for


nice edit there, i was just going to correct you PurloinedHeart Smile

the .= means that the following will be added to the var, instead of replacing it


Ahh, thanks. I just added it into my script and it's working beautifully, thanks much, problem solved
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Guest
PostPosted: Sat Aug 29, 2009 1:40 am    Post subject: Reply with quote
Highly wrote:

I'm going to try this one out, but a little help as to what it does?

What, did you not find the help file? It is there so you do not have to ask these kind of questions.
Look at topic Variables and Expressions. If you had read that, you would not have had to ask the first question.
Quote:
for example, Var //= 2 performs floor division to divide Var by 2, then stores the result back in Var. Similarly, Var .= "abc" is a shorthand way of writing Var := Var . "abc".
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Highly



Joined: 29 Aug 2009
Posts: 4
PostPosted: Sat Aug 29, 2009 1:44 am    Post subject: Reply with quote
Anonymous wrote:
Highly wrote:

I'm going to try this one out, but a little help as to what it does?

What, did you not find the help file? It is there so you do not have to ask these kind of questions.
Look at topic Variables and Expressions. If you had read that, you would not have had to ask the first question.
Quote:
for example, Var //= 2 performs floor division to divide Var by 2, then stores the result back in Var. Similarly, Var .= "abc" is a shorthand way of writing Var := Var . "abc".


Sorry, I had read that and and did not understand it to be applicable to my situation, because I misread terminology etc. I read all of the help files including the word string in them, I guess it was just an error through my incompetence. Again, sorry
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jaco0646



Joined: 07 Oct 2006
Posts: 3113
Location: MN, USA
PostPosted: Sat Aug 29, 2009 2:02 am    Post subject: Reply with quote
To be fair, there is an awful lot of information in that expression operators table; and I doubt anyone would grasp all of it in one reading. There is no need to apologize, that's what the help forum is here for. It was an honest question.
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