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jl34567
Joined: 03 Jan 2010
Posts: 262
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 Posted: Fri Mar 05, 2010 12:38 am Post subject: Any way to easily: if last sring ends with %x%, trim %x% |
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| Subject pretty much says it all..... |
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entropic
Joined: 21 Dec 2008
Posts: 181
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| Posted: Fri Mar 05, 2010 12:56 am Post subject: |
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Here's a way of doing it without regular expressions
| Code: |
removeChar = x
str = The quick brown fox jumps over the lazy dog.x
str2 = The quick brown fox jumps over the lazy dog.
Msgbox % "Start String: " str "`nPossibly Trimmed String: " RemoveLast(str , removeChar)
Msgbox % "Start String: " str2 "`nPossibly Trimmed String: " RemoveLast(str2, removeChar)
Return
RemoveLast(Haystack, Needle)
{
return SubStr(Haystack, 0, 1) = Needle ? SubStr(Haystack, 1, -1) : Haystack
}
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da_boogie_man
Guest
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| Posted: Fri Mar 05, 2010 1:04 am Post subject: |
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A simple way:
| Code: |
If SubStr(myVar, 0) = a
StringTrimRight, myVar, myVar, 1
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DBM |
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entropic
Joined: 21 Dec 2008
Posts: 181
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| Posted: Fri Mar 05, 2010 1:55 am Post subject: |
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Here's how to do it with regular expressions
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str = This is a test
var = t
Msgbox % RegExReplace(str, var "$")
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