AutoHotkey Community

[PhiLho]

Edited my first post so the first function follows more my coding rules (these functions will go in my function library) and to post the two others.
Of course, these are only one way to do this, there may be other tricks and al. Laszlo and toralf would remove some braces and pull out some obscure tricks. But they seems to be a good compromise between readability (what is the logic behind the code) and optimization (strings are small, so over-optimizing may be fun, but quite useless).
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vPhiLho := RegExReplace("Philippe Lhoste", "^(\w{3})\w*\s+\b(\w{3})\w*$", "$1$2")

[SKAN]

Dear PhiLho,

[PhiLho]

No, it is very close of my algorithm, without parsing and without removing the 0x prefix.
Of course, if any value is above 255, you get problems.
And it has a flaw, like my code (which I corrected and updated): for 0, 5, 0, it gives 0x500, no 0x000500.
Please, can you remove your quotes of my code, as I update my original post but the old code is still in your messages? Thank you.
Of course, you are free to post any variation of my code as you feel it.
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vPhiLho := RegExReplace("Philippe Lhoste", "^(\w{3})\w*\s+\b(\w{3})\w*$", "$1$2")

[SKAN]

Dear PhiLho,

[Titan]

ownage (req. 1.0.46.x+) :

[robiandi]

@Goyyah:
Today your string manipulation functions have been very useful for me. Many thanks.

[SKAN]

[SKAN]

[Laszlo]

Nice find, as always!
To handle leading 0's, this looks better

[SKAN]

Dear Laszlo,

[Laszlo]

"BGR=000000%BGR%" inserts 0's in the front. It is OK, but needs an extra instruction to remove 0x first. The easiest is to add 0x1000000 to the dll result (instead of +0). That makes the result always 7 hex digits, and you just cut the digits needed.

[SKAN]

[Laszlo]

(I sent my post too fast. See edit above. Both versions should be the same, because adding 0x1000000 does not cause a carry.)

[SKAN]

[SKAN]