As we know, many of operators in V2 have a corresponding assignment operator. a:=a+b is equivalent to a+=b, a:=a&b is equivalent to a&=b. It seems that there is no mater for ?? to also have one, i.e.a:=a??b will be totally equivalent to a?=b. How fortunately, when ? is closely followed by =, it will not be hard for the parser to handle, I guess, despite that ternary operator also contains a ?.
Of course, it's not a must to implement this feature right now. But codes will obviously become simpler if supported. Whenever and wherever you want to handle some "maybe-unset" variables, you will probably enjoy a smooth coding with ?= in V2.
