The input issue between dictionary Topic is solved

[dsewq1LYJ]

Hi Guys

Today I met a problem.

If you try to using "Input" command to retrieve the user input.

The command always treat "0 to 9"(digits) as "Integer".
You can check it with

Code: Select all

Input,foo,L1
if foo is integer
  ToolTip ...it's an integer

and if you try to use the output(digits) for a dictionary, that's definitely won't work.

e.g.

Code: Select all

dict = {}
dict.Insert("1", "foo")

Input,uin,L1
ToolTip dict[uin] ; It's same as dict[1], not dict["1"]

so I try to solve this problem by some trick.
Try to fool the interpreter force to convert Integer into String.

1. Not work

Code: Select all

Input,uin,L1
uin := uin ""

2. Not work

Code: Select all

Input,uin,L1
uin := uin . ""

3. Not work

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Input,uin,L1
uin := uin " "
StringTrimRight,uin,uin,1

...all of those methods just not working.
Is it possible solve this cleanly?

[gregster]

Tricky, but this works:

Code: Select all

dict := {"1": "foo"}
Input,uin,L1
msgbox % dict["" uin ""] 
ExitApp

Two " in an expression ("") create a literal " . With the integer in between you can create a string... and this gets you dict["1"]

[dsewq1LYJ]

Tricky, but this works:

Code: Select all

dict := {"1": "foo"}
Input,uin,L1
msgbox % dict["" uin ""] 
ExitApp

Two " in an expression ("") create a literal " . With the integer in between you can create a string... and this gets you dict["1"]

Damn man.

Well done. Cool sheep