StringTrimRight deprecated, what newer method? Topic is solved

[richolland]

I try to avoid deprecated methods, so I'm trying to find if there is a newer/better way that replaces "StringTrimRight" that I'm just not understanding?

I want an easy way to trim the last three characters from the right of strings which are of varied lengths, such as: 3043, 75607, 159887? This was very simple with the deprecated StringTrimRight.

Neither SubStr() nor rtrim() seem to do this with variable strings of unknown length.

This gives me what I want, but but is there a "newer" way that's not obsolete?

Code: Select all

InVar = 41085	; 3043, 159887
StringTrimRight, OutVar, InVar, 3
MsgBox,1, MESSAGE TITLE, %OutVar%, 10

--
Thank you very much
RH

[gregster]

Try SubStr's length parameter (third one; optional)

Code: Select all

InVar = 41085	; 3043, 159887
OutVar := SubStr(InVar, 1, -3)
MsgBox,1, MESSAGE TITLE, %OutVar%, 10

You can also specify a negative Length to omit that many characters from the end of the returned string

[sofista]

Or a regex approach

Code: Select all

InVar = 41085	; 3043, 159887
OutVar := RegExReplace(InVar, ".*\K\d{3}")
MsgBox,1, MESSAGE TITLE, %OutVar%, 10

This pattern only deals with numbers, as example data show, but you could use .*\K.{3} for any other character.

[teadrinker]

Or a regex approach

Code: Select all

InVar := 41085
MsgBox % RegExReplace(InVar, "...$")

[sofista]

Or a regex approach

Code: Select all

InVar := 41085
MsgBox % RegExReplace(InVar, "...$")

C'mon @teadrinker you'll make people think that regex is simple and easy to understand

[teadrinker]

Ha-ha

[richolland]

These all worked. I clicked "Accept answer" to the first one, though each functions well. And most importantly, they're simple enough for me.
Thank y’all very much.

r.h.

Code: Select all

InVar = 41085	; 3043, 159887
OutVar := SubStr(InVar, 1, -3)
MsgBox,1, MESSAGE TITLE, %OutVar%

Code: Select all

InVar = 41085	; 3043, 159887
OutVar := RegExReplace(InVar, ".*\K\d{3}")
MsgBox,1, MESSAGE TITLE, %OutVar%

Code: Select all

InVar = 41085	; 3043, 159887
MsgBox % RegExReplace(InVar, "...$")

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