how to grab part of the string before 'S??E??' ? Topic is solved

[brotherS]

I want to use this as part of a script where the input is something like

Some.Text.S01E05.More.Text.Here or
Different.Text.Now.S11E02.Even.More.Text.Here

and the output I want is

Some.Text
Different.Text.Now

It's probably really easy with RegEx, but how?

[boiler]

Code: Select all

Text =
(
Some.Text.S01E05.More.Text.Here or
Different.Text.Now.S11E02.Even.More.Text.Here
)

; store matches in array:
Matches := []
loop, Parse, Text, `n, `r
{
	RegExMatch(A_LoopField, ".*(?=\.S\d\dE\d\d)", M)
	Matches.Push(M)
}

; display contents of array:
for Each, Match in Matches
	Out .= Match "`n"
MsgBox, % Out

[brotherS]

Sorry, I can't get it to work properly, and it might be my fault. What I meant in my post above is that the input is something like

Some.Text.S01E05.More.Text.Here

or

Different.Text.Now.S11E02.Even.More.Text.Here

and the output I want is

Some.Text

or

Different.Text.Now

So there's only ever one line of input.

[boiler]

Code: Select all

Text := "Some.Text.S01E05.More.Text.Here"
RegExMatch(Text, ".*(?=\.S\d\dE\d\d)", Match)
MsgBox, % Match

[Chunjee]

It's probably really easy with RegEx, but how?

Use the right Regex pattern

https://regex101.com/ may help visualize

[boiler]

FYI - My code uses the right RegEx pattern.

[brotherS]

Thanks, boiler, you're the best! Works perfectly now.

Thanks Chunjee, I'll have a look.

[brotherS]

I want to expand the script where I'm using this, how would I still have

Some.Text.S01E05.More.Text.Here

as input and

Some.Text.S01E05

as a secondary output (as another string)?

[boiler]

Code: Select all

Text := "Some.Text.S01E05.More.Text.Here"
RegExMatch(Text, "(.*)\.S\d\dE\d\d", Match)
MsgBox, % Match1 "`n" Match

[brotherS]

Perfect, thanks again!