I'm trying to figure out for this code but with yesterday's date.
::td::
SendInput %A_YYYY%.%A_MM%.%A_DD% -{Space}
return
My Current code brings it to this: "2023.02.01 - " I'm looking for the same thing but with the date from yesterday.
Can anyone help?
Help with yesterday date Topic is solved
Re: Help with yesterday date Topic is solved
Code: Select all
::yd::
Yesterday := A_Now
Yesterday += -1, d
FormatTime, Yesterday, % Yesterday, % "yyyy.MM.dd - "
SendInput % Yesterday
return