testing is alpha...

[paik1002]

I am having trouble understanding the following basic code:

Code: Select all

q::
{
    mystring1 = A
    mystring2 = ?
    mystring3 = 1

    if (mystring1 is alpha)
    {  
        msgbox %mystring1% is an alphabet
    }        
    
    if (mystring2 is alpha)
    {  
        msgbox %mystring2% is an alphabet
    }        

    if (mystring3 is alpha)
    {  
        msgbox %mystring3% is an alphabet
    }        
}
return

The result of executing the above code:
A is an alphabet
? is an alphabet
1 is an alphabet

What is happening here? Very confused.

[Xtra]

Code: Select all

q::
{
    mystring1 = A
    mystring2 = ?
    mystring3 = 1
 
    if mystring1 is alpha
        msgbox %mystring1% is an alphabet      
 
    if mystring2 is alpha
        msgbox %mystring2% is an alphabet     
 
    if mystring3 is alpha
        msgbox %mystring3% is an alphabet    
}
return

Try it like this.

[Blackholyman]

try and remove the ()

Code: Select all

mystring1 = !
 
    if mystring1 is alpha
    {  
        msgbox %mystring1% is an alphabet
    }        

[Xtra]

sry its late i forgot to add this:

Note: The operators "between", "is", "in", and "contains" are not supported in expressions.

HTH

[paik1002]

O.K. removing the () did it. But still very strange that these operators are not supported inexpressions!
However, they were to be use in expressions, would there be other ways (tips & tricks?) of achieving it?

[Exaskryz]

Using RegEx of some sort should be a way to test it. You can reference this recent thread: https://autohotkey.com/boards/viewtopic.php?f=5&t=11437 The way I went about it replacing the entire string is probably an inefficient way, but it works. (I'm rather very rubbish at RegEx.)

For alpha, this should work:

Code: Select all

string:="abckljakjalkdjfakljfa"
If !(x:=RegExReplace(string,"\w","")) ; if all characters are letters ("word characters"), then x will be null, and thus false. So then the logical-not (!) makes it true
MsgBox string is alpha
return