how to replace a middot "·" Topic is solved

[Maxsteinfeld]

Hi
how can i replace a middot "·" (ISO-8859-1: hex B6, dez 183) in a string (e.g. line1) with a comma "," ?

StringReplace, line1, line1,  ·,% ",", All
does not match

regards
Max

[Nightwolf85]

This appears to work for me:

Code: Select all

line1 := StrReplace(line1, "·", ",")

Edit: So does your initial code actually. So not sure my version is any better.

[Maxsteinfeld]

This appears to work for me:

Code: Select all

line1 := StrReplace(line1, "·", ",")

Edit: So does your initial code actually. So not sure my version is any better.

Thx
That code works
Best regards

[jeeswg]

@Maxsteinfeld: Your original code works for me, although I would recommend to use StrReplace, as StringReplace won't be available in AHK v2.

Code: Select all

q::
line1 := "a·a"
line1 := StrReplace(line1, Chr(183), ",")
MsgBox, % line1

line1 := "a·a"
StringReplace, line1, line1,  ·,% ",", All
MsgBox, % line1
return

One possibility is that the character looks like Chr(183) but isn't, so I would check the char number for each character, see 'LIST ALL CHARACTERS THAT APPEAR IN A STRING' here for an example:
jeeswg's characters tutorial - AutoHotkey Community
https://autohotkey.com/boards/viewtopic.php?f=7&t=26486

Btw I was wondering about hex and 'dez', although it looks like 'dez' may be German for 'dec'.

[Maxsteinfeld]

Hi Jeeswg,
you are right - no idea why the line:
StringReplace, line1, line1, ·,% ",", All
had not worked for me - it works now
(perhaps i do not reload the script)
and many thanks for the links
regards
Max (German)