Regex to replace double quotes

[john_c]

Can anybody help with this code? Thanks.

( I've already tried some different ways of escaping, but can't figure out how to make it work)

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; desired result:
; "foo foo", "bar bar", "baz baz"

myVar = "foo foo, ""bar bar, ""baz baz"
myvar := RegExReplace(myVar, ", `"", "`", ")
MsgBox, %myVar%

[A_AhkUser]

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myVar := "foo foo, ""bar bar, ""baz baz"
myvar := RegExReplace(myVar, """", "blabla")
MsgBox % myVar

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myVar = "foo foo, ""bar bar, ""baz baz"
myvar := RegExReplace(myVar, """", "blabla")
MsgBox % myVar

See especially the documentation @ Variables and expressions:

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[in an expression](...)To include an [two] actual quote-character inside a literal string, specify two [four] consecutive quotes

yet functions parameters are evaluated as expressions.

Hope this helps.


[EDIT] both examples are intended to illustrate the difference between Myvar= vs MyVar := which one setting an expression using the colon-equal operator.

[john_c]

Hope this helps.

Yes, it works, thanks.

[slyfox1186]

Late reply but I suppose better than never.

Finds all double quotes stored in the Clipboard variable and replaces them with a single quote.

Examples:

Find: ""C:\path\to\file.txt""
Replace with: "C:\path\to\file.txt"

Find: "C:\path\to\AutoHotkey.exe" ""C:\path\to\file.txt""
Replace with: "C:\path\to\AutoHotkey.exe" "C:\path\to\file.txt"

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Clipboard := RegExReplace(Clipboard, "(""){2}", """")
MsgBox, % Clipboard
Return

[mikeyww]

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str      = "foo foo, ""bar bar, ""baz baz"
old      = , "
replace := """, "
out     := StrReplace(str, old, replace)
MsgBox, 64, Result, %out%