How to call nested function? Topic is solved

[jsong55]

Code: Select all

fn1()
    {
        fn2()
        {

        }
    }

[niCode]

Normally the point of nested functions is to encapsulate it so it is scoped to only the "parent" function. It only seems logical to just take the functions out so they can be globally seen.

But if you still insist on knowing how it can be done, one way to do this is dereferencing.

Code: Select all

fn1(function) {
    %function%()

    fn2() {
        MsgBox('first nested function called')
    }

    fn3() {
        MsgBox('second nested function called')
    }
}

fn1('fn2')
fn1('fn3')

[lexikos]

The simplest answer to "How to call nested function?" is literally fn2() within f1.

What niCode demonstrated is not something I would ever suggest doing in a real script.

A more typical use of a nested function would be to return it, as in the first closure example. The caller can then assign the return value to a variable or whatever, and call it via the variable. There are any number of other ways that a value can be passed from one part of the script to another. Just treat the nested function as a value, and do whatever needs to be done to get it where you want it.

If these are not the answers you are looking for, ask a more specific question.

[jsong55]

Thanks! Yes I think my use case is such where I build the gui with a function

Code: Select all

BuildGui()

Then I added a button and have a nested function

Code: Select all

BtnClicked(*)

Now somewhere else in the code I want to run the BtnClicked function, without having to Focus the Control and Send {enter} as the Gui Window may not be active.

Perhaps I need to use SendMessage?

But not familiar with SendMessage.

say the btn is in

Code: Select all

app:=Gui()
app.Add("Button","xm y+0" " w100" " vBtn1","Make Change")"

we could use the Hwnd with

Code: Select all

app["Btn1"].Hwnd

[lexikos]

@jsong55 Do you want us to guess at the structure of your script, like we had to guess at what you were trying to do?

Don't use SendMessage to call your own function. If you want your function to be callable from outside the function, either just don't put it inside the function, or pass it out somehow (e.g. attach it to the Gui as a method).

Normally the point of nested functions is to encapsulate it so it is scoped to only the "parent" function. It only seems logical to just take the functions out so they can be globally seen.

[jsong55]

Oh Brilliant suggestion. I did just that. Used BoundFunc to attach it to the Gui object as a method.
So now it can be called anywhere.

[jsong55]

@lexikos
Sorry to make you guess. I'll use example code next time I ask the question.

[iPhilip]

Used BoundFunc to attach it to the Gui object as a method.

I am not sure how you did that.

Here's my implementation using the DefineProp method:

Code: Select all

MyGui := BuildGui()
MyGui.Show()

F3::MyGui.Click()

BuildGui() {
   MyGui := Gui()
   Button := MyGui.Add('Button', , 'OK')
   Button.OnEvent('Click', Button_Click)
   MyGui.DefineProp('Click', {Call: (this) => Button_Click()})
   return MyGui
   Button_Click(*) {
      MsgBox A_ThisFunc
   }
}

[rommmcek]

I am not sure how you did that.

Replacing MyGui.DefineProp('Click', {Call: (this) => Button_Click()}) in your script with ObjBindMethod(myGui, 'Click') will do it.

[iPhilip]

Replacing MyGui.DefineProp('Click', {Call: (this) => Button_Click()}) in your script with ObjBindMethod(myGui, 'Click') will do it.

That didn't work for me. The closest thing was to replace MyGui.DefineProp('Click', {Call: (this) => Button_Click()}) with MyGui.Click := Button_Click.

[jsong55]

Code: Select all

MyGui.Click := Button_Click

This works. I used this too.

[rommmcek]

Interesting! However, for me MyGui.Click := Button_Click does not work.
Try then myGui.Button:= ObjBindMethod(myGui, 'Click').
Using AutoHotkey 2.0.3 Unicode 64-bit on Win10.

[jsong55]

@rommmcek
try

Code: Select all

MyGui.Click:=Button_Click.Bind()

[rommmcek]

Works, thanks!

[xMaxrayx]

Code: Select all

fn1()
    {
        fn2()
        {

        }
    }

like this

Code: Select all

fn1(mode := 1)
{
	if mode == 2{
	fn2()
	}
}

[jsong55]

@xMaxrayx thanks for your contribution but the context of my question wasn't clear. And in that context lexikos answer is best and I have marked his