Script to close application after opening PC

[AmDeG 11]

Which would be the script to close an application that is opened through the Start up, exactly 4 minutes after the computer has been turned on? It is this a Skype window. thanks

[empardopo]

Perhaps, you can use a bat file ...

Code: Select all

REM pause for 240 seconds:
timeout /t 240
REM Kill the program:
taskkill /im ProgramName /f

Greetings!

[AmDeG 11]

but is it possible as a autorun ahk script?

[ahcahc]

Code: Select all

#Persistent
#SingleInstance Ignore
SetTimer, check_skype, 1000
return

check_skype:
Process, Exist, skype.exe
if(errorlevel!=0)
{
Process, close, skype.exe
RunWait, %comspec% /c taskkill /f /im skype.exe, , hide
ExitApp
}
elapse := A_TickCount/1000/60
if (elapse>5)  ;pc was already powered-on for at least 5 minutes
	ExitApp
return

[AmDeG 11]

thanks for the script but this scripts is killing my whole Skype and I need just to close a second Skype that I open at the Startup in order to keep my Skype online. Could you tweak that?

[AmDeG 11]

I was able to do it! Thank you

[lexikos]

Why don't you just turn off auto-start within Skype?