Why ARGB convert to RGB with missing "Number0" ? Topic is solved

[fiendhunter]

I have 2 color to convert RGB;
FF23352A it returns 0x23352A
but FF05110A it returns 0x5110A

Code: Select all

SetFormat, Integer, H
pToken := Gdip_Startup()
pBitmap := Gdip_CreateBitmapFromHBITMAP(HSplashScreenChoose)
ARGB := Gdip_GetPixel( pBitmap, 283, 53 )                                ; ARGB := FF05110A
RGB := ARGB & 0xffffff
Gdip_DisposeImage(pBitmap)
Gdip_Shutdown(pToken)
SetFormat, Integer, D
msgbox % RGB
return

am I missing someting? I search for this issue. All answers; 5110A and 05110A are same (but 5110A is not work for lateron

[mikeyww]

You are not missing something. As you noted, the numbers are the same. You can add leading zeroes if needed for some uses.

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For each, argb in [0xFF23352A, 0xFF05110A]
 MsgBox, 0, Colors, % "ARGB = " Format("{:06x}", argb) "`n`n RGB = " Format("{:06x}", argb & 0xFFFFFF)

[fiendhunter]

You are not missing something. As you noted, the numbers are the same. You can add leading zeroes if needed for some uses.

Code: Select all

For each, argb in [0xFF23352A, 0xFF05110A]
 MsgBox, 0, Colors, % "ARGB = " Format("{:06x}", argb) "`n`n RGB = " Format("{:06x}", argb & 0xFFFFFF)

Thy. it works well. I ll check "Format" for more.

curious...

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StringTrimLeft, RGBval,  ARGB, 4

can output abnormal value? or identicle same as

Code: Select all

RGBval := Format("{:06x}", argb & 0xFFFFFF)

[mikeyww]

You can answer that question by testing a few values with which you are already working. The answer will, I believe, depend on whether you are working with numbers that always have exactly the same number of characters.

[fiendhunter]

You can answer that question by testing a few values with which you are already working. The answer will, I believe, depend on whether you are working with numbers that always have exactly the same number of characters.

My all tests, output same value. but I wont trust the results. RGBval := Format("{:06x}", argb & 0xFFFFFF) is working well with no question

thank you again.

[mikeyww]

I guess you would need to test something with a small "A" value, but OK if the current approach works. Enjoy!